← Blocks

Voltage Divider

Signal

Overview

A voltage divider is a resistive network that produces an output voltage equal to a fixed fraction of its input. Two resistors in series across a supply form the divider; the output is tapped between them. It is one of the most fundamental circuits in electronics.

In a FSAE, voltage dividers appear wherever a voltage is measured by a low-voltage circuit, a signal must be level-shifted before entering an ADC or comparator input, or for scaling a 5 V sensor output down to the 3.3 V range of a microcontroller ADC. They also appear in high-voltage measurement circuits, where the TS bus voltage (200–600 V) must be reduced to less than a 5V-level signal for monitoring - as in the Precharge.

Circuit description

R1 connects from the input to the output node. R2 connects from the output node to ground. Current flows from VinV_{in} through R1 and R2 to ground; the output voltage is the voltage developed across R2.

Basic voltage divider

The output voltage is:

Vout=Vin×R2R1+R2V_{out} = V_{in} \times \frac{R2}{R1 + R2} \\[0.5cm]

Worked example - scale 5 V to 3.3 V:

With R1 = 10 kΩ and R2 = 20 kΩ, the divider ratio is 20/(10+20) = 2/3. At VinV_{in} = 5 V, VoutV_{out} = 3.33 V. This is a useful starting point when interfacing a 5 V analogue signal to a 3.3 V ADC input.

Design notes

P=Vin2R1+R2P = \frac{V_{in}^2}{R1 + R2}\\[0.5cm]

For a 5 V supply across 30 kΩ total, this is about 0.83 mW - negligible. For high-voltage dividers the power may become significant.

High-voltage construction

When dividing down a high voltage such as the TS bus (200 to 600 V), the voltage drop across R1 is large and will exceed the rating of most small parts. You could always use a high-voltage resistor, but these are exotic and more expensive.

One solution is to construct R1 from several equal-value resistors in series. The total voltage across R1 is divided equally across each series element. Choose the number of segments so that no single resistor exceeds its voltage rating - the 1206 package has generous pad spacing and is usually rated for 200V.

Vper-resistor=VinVoutNV_{per\text{-}resistor} = \frac{V_{in} - V_{out}}{N}\\[0.5cm]

Where NN is the number of series segments.

High-voltage voltage divider with series R1

The resistors that make up R1 must all be equal value. If mixed values are used, the voltage drop will not be uniform and may exceed the individual rating of one or more segments.

Worked example - 600 V TS bus to 12 V analogue signal:

Target: VinV_{in} = 600 V, VoutV_{out} = 12 V, 1206 package resistors (200 V max, 250 mW rated).

  1. Choose R2 = 47 kΩ.

  2. From the divider formula, R1total=R2×(Vin/Vout1)=47k×(600/121)2.303MΩR_{1\mathrm{total}} = R2 × (V_\mathrm{in}/V_\mathrm{out} − 1) = 47\mathrm{k} × (600/12 − 1) ≈ 2.303 MΩ.

    Use R1total=2.3MΩR_{1\mathrm{total}} = 2.3\mathrm{M}\Omega

  3. Voltage across R1total=60012=588VR_{1\mathrm{total}} = 600 − 12 = 588\,\mathrm{V} and quiescent current I=588/2.3MΩ=0.26mAI = 588 / 2.3\,\mathrm{M}\Omega = 0.26\,\mathrm{mA}

  4. Voltage constraint (200 V per 1206): minimum segments = 588/200=2.94588 / 200 = 2.94

    Minimum is very nearly a whole number. Choose four resistors for safety.

  5. Power constraint (250 mW per 1206): power per segment = V2/(R1N)=5882/(2.3×106×4)=38mWV^2 / (R_1 N) = 588² / (2.3\times 10^{6} \times 4) = 38\,\mathrm{mW} per segment. Well below 250mW

  6. Use 5 × 464 kΩ 1206 in series (= 2.32 MΩ) for Voltage derating margin (component quality, creepage due to impurities on board etc):

    • Voltage per resistor: 588V/5=117.6V588\,\mathrm{V} / 5 = 117.6\,\mathrm{V} -> 40% safety factor for 1206 resistors
    • Power per resistor: 5882V/(2.32MΩ)/5=31mW588^2\,\mathrm{V} / (2.32\,\text{M}\Omega) / 5 = 31\,\mathrm{mW}

We built in two resistors worth of safety factor in R1 for this design. We added one because the minimum segements was very close to a whole number (2.94 resistors required) and another to account for other factors like impurities building up on the PCB, component quality, transient voltages that may appear on the HV bus etc. We want this part of the circuit to be absolutely bullet-proof - any high-current failure mode here will simply vaporise the PCB traces.

This solution could be optimised for lower impedance by eg. reducing R2R_2 and re-solving for low voltages and power in R1totalR_{1\text{total}}

It ought to be fine for input into eg. a comparator which has a very high input impedance.

Package voltage and power ratings (common SMD resistors):

PackageMax working voltageTypical power rating
040250 V63 mW
060375 V100 mW
0805150 V125 mW
1206200 V250 mW

Gotchas